How to create an object from a dictionary with dot access — without classes and dataclasses?

When you're working with JSON, configurations, or APIs, constant access via dict['key'] clutters the code and worsens readability:

data = {"host": "localhost", "port": 5432}
data["host"]

SimpleNamespace gives the same result, but with dot access:

cfg = SimpleNamespace(**data)
print(cfg.host)

In this case, the object remains dynamic, and you can add fields:

cfg.debug = True

However, the keys must be valid attribute names, and this only works for flat dictionaries (nesting is not converted).

🔥Convenient for prototyping, testing, and simple data.

#Python #DataStructures #SimpleNamespace #CodingTips #DevTools #Programming

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