leetcode.cn 2025-10-23
🟢3461.check-if-digits-are-equal-in-string-after-operations-i
🏷️ Tags
#math #string #combinatorics #number_theory #simulation
🟢3461.check-if-digits-are-equal-in-string-after-operations-i
🏷️ Tags
#math #string #combinatorics #number_theory #simulation
Telegraph
check-if-digits-are-equal-in-string-after-operations-i
给你一个由数字组成的字符串 s 。重复执行以下操作,直到字符串恰好包含 两个 数字:
leetcode.com 2025-10-23
🟢3461.check-if-digits-are-equal-in-string-after-operations-i
🏷️ Tags
#math #string #combinatorics #number_theory #simulation
🟢3461.check-if-digits-are-equal-in-string-after-operations-i
🏷️ Tags
#math #string #combinatorics #number_theory #simulation
Telegraph
check-if-digits-are-equal-in-string-after-operations-i
You are given a string s consisting of digits. Perform the following operation repeatedly until the string has exactly two digits:
❤1
leetcode.cn 2025-12-10
🟡3577.count-the-number-of-computer-unlocking-permutations
🏷️ Tags
#brainteaser #array #math #combinatorics
🟡3577.count-the-number-of-computer-unlocking-permutations
🏷️ Tags
#brainteaser #array #math #combinatorics
Telegraph
count-the-number-of-computer-unlocking-permutations
给你一个长度为 n 的数组 complexity。 在房间里有 n 台 上锁的 计算机,这些计算机的编号为 0 到 n - 1,每台计算机都有一个 唯一 的密码。编号为 i 的计算机的密码复杂度为 complexity[i]。 编号为 0 的计算机密码已经 解锁 ,并作为根节点。其他所有计算机必须通过它或其他已经解锁的计算机来解锁,具体规则如下:
leetcode.com 2025-12-10
🟡3577.count-the-number-of-computer-unlocking-permutations
🏷️ Tags
#brainteaser #array #math #combinatorics
🟡3577.count-the-number-of-computer-unlocking-permutations
🏷️ Tags
#brainteaser #array #math #combinatorics
Telegraph
count-the-number-of-computer-unlocking-permutations
You are given an array complexity of length n. There are n locked computers in a room with labels from 0 to n - 1, each with its own unique password. The password of the computer i has a complexity complexity[i]. The password for the computer labeled 0 is…
leetcode.cn 2026-07-17
🔴3312.sorted-gcd-pair-queries
🏷️ Tags
#array #hash_table #math #binary_search #combinatorics #counting #number_theory #prefix_sum
🔴3312.sorted-gcd-pair-queries
🏷️ Tags
#array #hash_table #math #binary_search #combinatorics #counting #number_theory #prefix_sum
Telegraph
sorted-gcd-pair-queries
给你一个长度为 n 的整数数组 nums 和一个整数数组 queries 。 gcdPairs 表示数组 nums 中所有满足 0 <= i < j < n 的数对 (nums[i], nums[j]) 的 最大公约数 升序 排列构成的数组。 对于每个查询 queries[i] ,你需要找到 gcdPairs 中下标为 queries[i] 的元素。
leetcode.com 2026-07-17
🔴3312.sorted-gcd-pair-queries
🏷️ Tags
#array #hash_table #math #binary_search #combinatorics #counting #number_theory #prefix_sum
🔴3312.sorted-gcd-pair-queries
🏷️ Tags
#array #hash_table #math #binary_search #combinatorics #counting #number_theory #prefix_sum
Telegraph
sorted-gcd-pair-queries
You are given an integer array nums of length n and an integer array queries. Let gcdPairs denote an array obtained by calculating the GCD of all possible pairs (nums[i], nums[j]), where 0 <= i < j < n, and then sorting these values in ascending order. For…
leetcode.cn 2026-07-29
🔴3518.smallest-palindromic-rearrangement-ii
🏷️ Tags
#hash_table #math #string #combinatorics #counting
🔴3518.smallest-palindromic-rearrangement-ii
🏷️ Tags
#hash_table #math #string #combinatorics #counting
Telegraph
smallest-palindromic-rearrangement-ii
给你一个 回文 字符串 s 和一个整数 k。
leetcode.com 2026-07-29
🔴3518.smallest-palindromic-rearrangement-ii
🏷️ Tags
#hash_table #math #string #combinatorics #counting
🔴3518.smallest-palindromic-rearrangement-ii
🏷️ Tags
#hash_table #math #string #combinatorics #counting
Telegraph
smallest-palindromic-rearrangement-ii
You are given a palindromic string s and an integer k. Return the k-th lexicographically smallest palindromic permutation of s. If there are fewer than k distinct palindromic permutations, return an empty string. Note: Different rearrangements that yield…
leetcode.cn 2026-08-21
🔴3116.kth-smallest-amount-with-single-denomination-combination
🏷️ Tags
#bit_manipulation #array #math #binary_search #combinatorics #number_theory
🔴3116.kth-smallest-amount-with-single-denomination-combination
🏷️ Tags
#bit_manipulation #array #math #binary_search #combinatorics #number_theory
Telegraph
kth-smallest-amount-with-single-denomination-combination
给你一个整数数组 coins 表示不同面额的硬币,另给你一个整数 k 。 你有无限量的每种面额的硬币。但是,你 不能 组合使用不同面额的硬币。 返回使用这些硬币能制造的 第 kth 小 金额。 示例 1: 输入: coins = [3,6,9], k = 3 输出: 9 解释:给定的硬币可以制造以下金额:3元硬币产生3的倍数:3, 6, 9, 12, 15等。6元硬币产生6的倍数:6, 12, 18, 24等。9元硬币产生9的倍数:9, 18, 27, 36等。所有硬币合起来可以产生:3, 6, 9…
leetcode.com 2026-08-21
🔴3116.kth-smallest-amount-with-single-denomination-combination
🏷️ Tags
#bit_manipulation #array #math #binary_search #combinatorics #number_theory
🔴3116.kth-smallest-amount-with-single-denomination-combination
🏷️ Tags
#bit_manipulation #array #math #binary_search #combinatorics #number_theory
Telegraph
kth-smallest-amount-with-single-denomination-combination
You are given an integer array coins representing coins of different denominations and an integer k. You have an infinite number of coins of each denomination. However, you are not allowed to combine coins of different denominations. Return the kth smallest…
leetcode.cn 2026-09-16
🟡1621.number-of-sets-of-k-non-overlapping-line-segments
🏷️ Tags
#math #dynamic_programming #combinatorics #prefix_sum
🟡1621.number-of-sets-of-k-non-overlapping-line-segments
🏷️ Tags
#math #dynamic_programming #combinatorics #prefix_sum
Telegraph
number-of-sets-of-k-non-overlapping-line-segments
给你一维空间的 n 个点,其中第 i 个点(编号从 0 到 n-1)位于 x = i 处,请你找到 恰好 k 个不重叠 线段且每个线段至少覆盖两个点的方案数。线段的两个端点必须都是 整数坐标 。这 k 个线段不需要全部覆盖全部 n 个点,且它们的端点 可以 重合。 请你返回 k 个不重叠线段的方案数。由于答案可能很大,请将结果对 109 + 7 取余 后返回。 示例 1: 输入:n = 4, k = 2 输出:5 解释:如图所示,两个线段分别用红色和蓝色标出。 上图展示了 5 种不同的方案 {(0,2)…
leetcode.com 2026-09-16
🟡1621.number-of-sets-of-k-non-overlapping-line-segments
🏷️ Tags
#math #dynamic_programming #combinatorics #prefix_sum
🟡1621.number-of-sets-of-k-non-overlapping-line-segments
🏷️ Tags
#math #dynamic_programming #combinatorics #prefix_sum
Telegraph
number-of-sets-of-k-non-overlapping-line-segments
Given n points on a 1-D plane, where the ith point (from 0 to n-1) is at x = i, find the number of ways we can draw exactly k non-overlapping line segments such that each segment covers two or more points. The endpoints of each segment must have integral…
leetcode.cn 2026-10-18
🔴1569.number-of-ways-to-reorder-array-to-get-same-bst
🏷️ Tags
#tree #union_find #binary_search_tree #memoization #array #math #divide_and_conquer #dynamic_programming #binary_tree #combinatorics #fermats_little_theorem
🔴1569.number-of-ways-to-reorder-array-to-get-same-bst
🏷️ Tags
#tree #union_find #binary_search_tree #memoization #array #math #divide_and_conquer #dynamic_programming #binary_tree #combinatorics #fermats_little_theorem
Telegraph
number-of-ways-to-reorder-array-to-get-same-bst
给你一个数组 nums 表示 1 到 n 的一个排列。我们按照元素在 nums 中的顺序依次插入一个初始为空的二叉搜索树(BST)。请你统计将 nums 重新排序后,统计满足如下条件的方案数:重排后得到的二叉搜索树与 nums 原本数字顺序得到的二叉搜索树相同。
leetcode.com 2026-10-18
🔴1569.number-of-ways-to-reorder-array-to-get-same-bst
🏷️ Tags
#tree #union_find #binary_search_tree #memoization #array #math #divide_and_conquer #dynamic_programming #binary_tree #combinatorics #fermats_little_theorem
🔴1569.number-of-ways-to-reorder-array-to-get-same-bst
🏷️ Tags
#tree #union_find #binary_search_tree #memoization #array #math #divide_and_conquer #dynamic_programming #binary_tree #combinatorics #fermats_little_theorem
Telegraph
number-of-ways-to-reorder-array-to-get-same-bst
Given an array nums that represents a permutation of integers from 1 to n. We are going to construct a binary search tree (BST) by inserting the elements of nums in order into an initially empty BST. Find the number of different ways to reorder nums so that…