leetcode.cn 2026-04-15
🟢2515.shortest-distance-to-target-string-in-a-circular-array
🏷️ Tags
#array #string
🟢2515.shortest-distance-to-target-string-in-a-circular-array
🏷️ Tags
#array #string
Telegraph
shortest-distance-to-target-string-in-a-circular-array
给你一个下标从 0 开始的 环形 字符串数组 words 和一个字符串 target 。环形数组 意味着数组首尾相连。
leetcode.com 2026-04-15
🟢2515.shortest-distance-to-target-string-in-a-circular-array
🏷️ Tags
#array #string
🟢2515.shortest-distance-to-target-string-in-a-circular-array
🏷️ Tags
#array #string
Telegraph
shortest-distance-to-target-string-in-a-circular-array
You are given a 0-indexed circular string array words and a string target. A circular array means that the array's end connects to the array's beginning.
leetcode.cn 2026-05-21
🟡3043.find-the-length-of-the-longest-common-prefix
🏷️ Tags
#trie #array #hash_table #string
🟡3043.find-the-length-of-the-longest-common-prefix
🏷️ Tags
#trie #array #hash_table #string
Telegraph
find-the-length-of-the-longest-common-prefix
给你两个 正整数 数组 arr1 和 arr2 。 正整数的 前缀 是其 最左边 的一位或多位数字组成的整数。例如,123 是整数 12345 的前缀,而 234 不是 。 设若整数 c 是整数 a 和 b 的 公共前缀 ,那么 c 需要同时是 a 和 b 的前缀。例如,5655359 和 56554 有公共前缀 565 和 5655,而 1223 和 43456 没有 公共前缀。 你需要找出属于 arr1 的整数 x 和属于 arr2 的整数 y 组成的所有数对 (x, y) 之中最长的公共前缀的长度。…
leetcode.com 2026-05-21
🟡3043.find-the-length-of-the-longest-common-prefix
🏷️ Tags
#trie #array #hash_table #string
🟡3043.find-the-length-of-the-longest-common-prefix
🏷️ Tags
#trie #array #hash_table #string
Telegraph
find-the-length-of-the-longest-common-prefix
You are given two arrays with positive integers arr1 and arr2. A prefix of a positive integer is an integer formed by one or more of its digits, starting from its leftmost digit. For example, 123 is a prefix of the integer 12345, while 234 is not. A common…
leetcode.com 2026-05-25
🟡1871.jump-game-vii
🏷️ Tags
#string #dynamic_programming #prefix_sum #sliding_window
🟡1871.jump-game-vii
🏷️ Tags
#string #dynamic_programming #prefix_sum #sliding_window
Telegraph
jump-game-vii
You are given a 0-indexed binary string s and two integers minJump and maxJump. In the beginning, you are standing at index 0, which is equal to '0'. You can move from index i to index j if the following conditions are fulfilled: