You are given an integer side, representing the edge length of a square with corners at (0, 0), (0, side), (side, 0), and (side, side) on a Cartesian plane. You are also given a positive integer k and a 2D integer array points, where points[i] = [xi, yi]…

若旋转 4 次，则可以得到 [4,5,6,7,0,1,2]

Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become:

若旋转 4 次，则可以得到 [4,5,6,7,0,1,4]

Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,4,4,5,6,7] might become:

给你两个整数数组 nums1 和 nums2 ，它们已经按非降序排序，请你返回两个数组的 最小公共整数 。如果两个数组 nums1 和 nums2 没有公共整数，请你返回 -1 。 如果一个整数在两个数组中都 至少出现一次 ，那么这个整数是数组 nums1 和 nums2 公共 的。   示例 1： 输入：nums1 = [1,2,3], nums2 = [2,4] 输出：2 解释：两个数组的最小公共元素是 2 ，所以我们返回 2 。 示例 2： 输入：nums1 = [1,2,3,6], nums2 =…

Given two integer arrays nums1 and nums2, sorted in non-decreasing order, return the minimum integer common to both arrays. If there is no common integer amongst nums1 and nums2, return -1. Note that an integer is said to be common to nums1 and nums2 if both…

整数数组 nums 按升序排列，数组中的值 互不相同 。 在传递给函数之前，nums 在预先未知的某个下标 k（0 <= k < nums.length）上进行了 向左旋转，使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]]（下标 从 0 开始 计数）。例如， [0,1,2,4,5,6,7] 下标 3 上向左旋转后可能变为 [4,5,6,7,0,1,2] 。 给你 旋转后 的数组 nums 和一个整数 target…

There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly left rotated at an unknown index k (1 <= k < nums.length) such that the resulting array is [nums[k], nums[k+1], ...,…

有一条无限长的数轴，原点在 0 处，沿着 x 轴 正 方向无限延伸。 给你一个二维数组 queries ，它包含两种操作：