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Preparing for Data Science Interviews With LeetCode FAQs.pdf
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🔖 Preparing for Data Science Interviews
📝 With LeetCode FAQs

👨🏻‍💻 If you're aiming for top tech companies like Google or Amazon, it's natural to feel overwhelmed and unsure where to begin. I’ve been there too—facing tons of questions without a clear roadmap of what to study or when.

✏️ That’s why I decided to create a step-by-step plan for myself. In this guide, I’ve compiled the most frequently asked LeetCode questions, complete with solutions, techniques, and patterns to help you master the kinds of problems that big companies love to ask.

Whether you're just starting out or sharpening your interview skills, this resource is designed to give you clarity, focus, and confidence.

📂 Stay tuned — I’ll be sharing the full file soon!

#DataScience #InterviewPrep #LeetCode #CodingInterview #TechInterviews #GoogleInterview #AmazonInterview #Python #MachineLearning #AI #CareerTips


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In Python, the collections module offers specialized container datatypes that solve real-world coding challenges with elegance and efficiency. These tools are interview favorites for optimizing time complexity and writing clean, professional code! 💡
import collections  

# defaultdict - Eliminate key errors with auto-initialization
from collections import defaultdict
gradebook = defaultdict(int)
gradebook['Alice'] += 95
print(gradebook['Alice']) # Output: 95
print(gradebook['Bob']) # Output: 0

# defaultdict for grouping operations
anagrams = defaultdict(list)
words = ["eat", "tea", "tan"]
for w in words:
key = ''.join(sorted(w))
anagrams[key].append(w)
print(anagrams['aet']) # Output: ['eat', 'tea']

# Counter - Frequency analysis in one line
from collections import Counter
text = "abracadabra"
freq = Counter(text)
print(freq['a']) # Output: 5
print(freq.most_common(2)) # Output: [('a', 5), ('b', 2)]

# Counter arithmetic for problem-solving
inventory = Counter(apples=10, oranges=5)
sales = Counter(apples=3, oranges=2)
print(inventory - sales) # Output: Counter({'apples': 7, 'oranges': 3})

# namedtuple - Self-documenting data structures
from collections import namedtuple
Employee = namedtuple('Employee', 'name role salary')
dev = Employee('Alex', 'Developer', 95000)
print(dev.role) # Output: Developer
print(dev[2]) # Output: 95000

# deque - Optimal for BFS and sliding windows
from collections import deque
queue = deque([1, 2, 3])
queue.append(4)
queue.popleft()
print(queue) # Output: deque([2, 3, 4])
queue.rotate(1)
print(queue) # Output: deque([4, 2, 3])

# OrderedDict - Track insertion order (LRU cache essential)
from collections import OrderedDict
cache = OrderedDict()
cache['A'] = 1
cache['B'] = 2
cache.move_to_end('A')
cache.popitem(last=False)
print(list(cache.keys())) # Output: ['B', 'A']

# ChainMap - Manage layered configurations
from collections import ChainMap
defaults = {'theme': 'dark', 'font': 'Arial'}
user_prefs = {'theme': 'light'}
settings = ChainMap(user_prefs, defaults)
print(settings['font']) # Output: Arial

# Practical Interview Tip: Anagram detection
print(Counter("secure") == Counter("rescue")) # Output: True

# Pro Tip: Sliding window maximum
def max_sliding_window(nums, k):
dq, result = deque(), []
for i, n in enumerate(nums):
while dq and nums[dq[-1]] < n:
dq.pop()
dq.append(i)
if dq[0] == i - k:
dq.popleft()
if i >= k - 1:
result.append(nums[dq[0]])
return result
print(max_sliding_window([1,3,-1,-3,5,3,6,7], 3)) # Output: [3,3,5,5,6,7]

# Expert Move: Custom LRU Cache implementation
class LRUCache:
def __init__(self, capacity):
self.cache = OrderedDict()
self.capacity = capacity
def get(self, key):
if key not in self.cache:
return -1
self.cache.move_to_end(key)
return self.cache[key]
def put(self, key, value):
if key in self.cache:
del self.cache[key]
self.cache[key] = value
if len(self.cache) > self.capacity:
self.cache.popitem(last=False)
cache = LRUCache(2)
cache.put(1, 10)
cache.put(2, 20)
cache.get(1)
cache.put(3, 30)
print(list(cache.cache.keys())) # Output: [2, 1, 3] → Wait! Correction: Should be [1, 3] (capacity=2 triggers eviction of '2')

# Bonus: Multiset operations with Counter
primes = Counter([2, 3, 5, 7])
odds = Counter([1, 3, 5, 7, 9])
print(primes | odds) # Output: Counter({3:1, 5:1, 7:1, 2:1, 9:1, 1:1})


By: @DatascienceN🌟

#Python #CodingInterview #DataStructures #collections #Programming #TechJobs #Algorithm #LeetCode #DeveloperTips #CareerGrowth
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