leetcode.cn 2026-02-09
🟡1382.balance-a-binary-search-tree
🏷️ Tags
#greedy #tree #depth_first_search #binary_search_tree #divide_and_conquer #binary_tree
🟡1382.balance-a-binary-search-tree
🏷️ Tags
#greedy #tree #depth_first_search #binary_search_tree #divide_and_conquer #binary_tree
Telegraph
balance-a-binary-search-tree
给你一棵二叉搜索树,请你返回一棵 平衡后 的二叉搜索树,新生成的树应该与原来的树有着相同的节点值。如果有多种构造方法,请你返回任意一种。 如果一棵二叉搜索树中,每个节点的两棵子树高度差不超过 1 ,我们就称这棵二叉搜索树是 平衡的 。 示例 1: 输入:root = [1,null,2,null,3,null,4,null,null] 输出:[2,1,3,null,null,null,4] 解释:这不是唯一的正确答案,[3,1,4,null,2,null,null] 也是一个可行的构造方案。 示例 2:…
leetcode.com 2026-02-09
🟡1382.balance-a-binary-search-tree
🏷️ Tags
#greedy #tree #depth_first_search #binary_search_tree #divide_and_conquer #binary_tree
🟡1382.balance-a-binary-search-tree
🏷️ Tags
#greedy #tree #depth_first_search #binary_search_tree #divide_and_conquer #binary_tree
Telegraph
balance-a-binary-search-tree
Given the root of a binary search tree, return a balanced binary search tree with the same node values. If there is more than one answer, return any of them. A binary search tree is balanced if the depth of the two subtrees of every node never differs by…
leetcode.cn 2026-02-24
🟢1022.sum-of-root-to-leaf-binary-numbers
🏷️ Tags
#tree #depth_first_search #binary_tree
🟢1022.sum-of-root-to-leaf-binary-numbers
🏷️ Tags
#tree #depth_first_search #binary_tree
Telegraph
sum-of-root-to-leaf-binary-numbers
给出一棵二叉树,其上每个结点的值都是 0 或 1 。每一条从根到叶的路径都代表一个从最高有效位开始的二进制数。
leetcode.com 2026-02-24
🟢1022.sum-of-root-to-leaf-binary-numbers
🏷️ Tags
#tree #depth_first_search #binary_tree
🟢1022.sum-of-root-to-leaf-binary-numbers
🏷️ Tags
#tree #depth_first_search #binary_tree
Telegraph
sum-of-root-to-leaf-binary-numbers
You are given the root of a binary tree where each node has a value 0 or 1. Each root-to-leaf path represents a binary number starting with the most significant bit.
leetcode.cn 2026-04-21
🟡1722.minimize-hamming-distance-after-swap-operations
🏷️ Tags
#depth_first_search #union_find #array
🟡1722.minimize-hamming-distance-after-swap-operations
🏷️ Tags
#depth_first_search #union_find #array
Telegraph
minimize-hamming-distance-after-swap-operations
给你两个整数数组 source 和 target ,长度都是 n 。还有一个数组 allowedSwaps ,其中每个 allowedSwaps[i] = [ai, bi] 表示你可以交换数组 source 中下标为 ai 和 bi(下标从 0 开始)的两个元素。注意,你可以按 任意 顺序 多次 交换一对特定下标指向的元素。 相同长度的两个数组 source 和 target 间的 汉明距离 是元素不同的下标数量。形式上,其值等于满足 source[i] != target[i] (下标从 0 开始)的下标…
leetcode.com 2026-04-21
🟡1722.minimize-hamming-distance-after-swap-operations
🏷️ Tags
#depth_first_search #union_find #array
🟡1722.minimize-hamming-distance-after-swap-operations
🏷️ Tags
#depth_first_search #union_find #array
Telegraph
minimize-hamming-distance-after-swap-operations
You are given two integer arrays, source and target, both of length n. You are also given an array allowedSwaps where each allowedSwaps[i] = [ai, bi] indicates that you are allowed to swap the elements at index ai and index bi (0-indexed) of array source.…
leetcode.cn 2026-04-26
🟡1559.detect-cycles-in-2d-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
🟡1559.detect-cycles-in-2d-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
Telegraph
detect-cycles-in-2d-grid
给你一个二维字符网格数组 grid ,大小为 m x n ,你需要检查 grid 中是否存在 相同值 形成的环。 一个环是一条开始和结束于同一个格子的长度 大于等于 4 的路径。对于一个给定的格子,你可以移动到它上、下、左、右四个方向相邻的格子之一,可以移动的前提是这两个格子有 相同的值 。 同时,你也不能回到上一次移动时所在的格子。比方说,环 (1, 1) -> (1, 2) -> (1, 1) 是不合法的,因为从 (1, 2) 移动到 (1, 1) 回到了上一次移动时的格子。 如果 grid 中有相同值形成的环,请你返回…
leetcode.com 2026-04-26
🟡1559.detect-cycles-in-2d-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
🟡1559.detect-cycles-in-2d-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
Telegraph
detect-cycles-in-2d-grid
Given a 2D array of characters grid of size m x n, you need to find if there exists any cycle consisting of the same value in grid. A cycle is a path of length 4 or more in the grid that starts and ends at the same cell. From a given cell, you can move to…
leetcode.cn 2026-04-27
🟡1391.check-if-there-is-a-valid-path-in-a-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
🟡1391.check-if-there-is-a-valid-path-in-a-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
Telegraph
check-if-there-is-a-valid-path-in-a-grid
给你一个 m x n 的网格 grid。网格里的每个单元都代表一条街道。grid[i][j] 的街道可以是:
leetcode.com 2026-04-27
🟡1391.check-if-there-is-a-valid-path-in-a-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
🟡1391.check-if-there-is-a-valid-path-in-a-grid
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #array #matrix
Telegraph
check-if-there-is-a-valid-path-in-a-grid
You are given an m x n grid. Each cell of grid represents a street. The street of grid[i][j] can be:
leetcode.cn 2026-06-11
🟡3558.number-of-ways-to-assign-edge-weights-i
🏷️ Tags
#tree #depth_first_search #math
🟡3558.number-of-ways-to-assign-edge-weights-i
🏷️ Tags
#tree #depth_first_search #math
Telegraph
number-of-ways-to-assign-edge-weights-i
给你一棵 n 个节点的无向树,节点从 1 到 n 编号,树以节点 1 为根。树由一个长度为 n - 1 的二维整数数组 edges 表示,其中 edges[i] = [ui, vi] 表示在节点 ui 和 vi 之间有一条边。
leetcode.com 2026-06-11
🟡3558.number-of-ways-to-assign-edge-weights-i
🏷️ Tags
#tree #depth_first_search #math
🟡3558.number-of-ways-to-assign-edge-weights-i
🏷️ Tags
#tree #depth_first_search #math
Telegraph
number-of-ways-to-assign-edge-weights-i
There is an undirected tree with n nodes labeled from 1 to n, rooted at node 1. The tree is represented by a 2D integer array edges of length n - 1, where edges[i] = [ui, vi] indicates that there is an edge between nodes ui and vi. Initially, all edges have…
leetcode.cn 2026-06-12
🔴3559.number-of-ways-to-assign-edge-weights-ii
🏷️ Tags
#bit_manipulation #tree #depth_first_search #array #math #dynamic_programming
🔴3559.number-of-ways-to-assign-edge-weights-ii
🏷️ Tags
#bit_manipulation #tree #depth_first_search #array #math #dynamic_programming
Telegraph
number-of-ways-to-assign-edge-weights-ii
给你一棵有 n 个节点的无向树,节点从 1 到 n 编号,树以节点 1 为根。树由一个长度为 n - 1 的二维整数数组 edges 表示,其中 edges[i] = [ui, vi] 表示在节点 ui 和 vi 之间有一条边。
leetcode.com 2026-06-12
🔴3559.number-of-ways-to-assign-edge-weights-ii
🏷️ Tags
#bit_manipulation #tree #depth_first_search #array #math #dynamic_programming
🔴3559.number-of-ways-to-assign-edge-weights-ii
🏷️ Tags
#bit_manipulation #tree #depth_first_search #array #math #dynamic_programming
Telegraph
number-of-ways-to-assign-edge-weights-ii
There is an undirected tree with n nodes labeled from 1 to n, rooted at node 1. The tree is represented by a 2D integer array edges of length n - 1, where edges[i] = [ui, vi] indicates that there is an edge between nodes ui and vi. Initially, all edges have…
leetcode.cn 2026-07-04
🟡2492.minimum-score-of-a-path-between-two-cities
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
🟡2492.minimum-score-of-a-path-between-two-cities
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
Telegraph
minimum-score-of-a-path-between-two-cities
给你一个正整数 n ,表示总共有 n 个城市,城市从 1 到 n 编号。给你一个二维数组 roads ,其中 roads[i] = [ai, bi, distancei] 表示城市 ai 和 bi 之间有一条 双向 道路,道路距离为 distancei 。城市构成的图不一定是连通的。 两个城市之间一条路径的 分数 定义为这条路径中道路的 最小 距离。 返回城市 1 和城市 n 之间的所有路径的 最小 分数。 注意:
leetcode.com 2026-07-04
🟡2492.minimum-score-of-a-path-between-two-cities
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
🟡2492.minimum-score-of-a-path-between-two-cities
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
Telegraph
minimum-score-of-a-path-between-two-cities
You are given a positive integer n representing n cities numbered from 1 to n. You are also given a 2D array roads where roads[i] = [ai, bi, distancei] indicates that there is a bidirectional road between cities ai and bi with a distance equal to distancei.…
leetcode.cn 2026-07-11
🟡2685.count-the-number-of-complete-components
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
🟡2685.count-the-number-of-complete-components
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
Telegraph
count-the-number-of-complete-components
给你一个整数 n 。现有一个包含 n 个顶点的 无向 图,顶点按从 0 到 n - 1 编号。给你一个二维整数数组 edges 其中 edges[i] = [ai, bi] 表示顶点 ai 和 bi 之间存在一条 无向 边。 返回图中 完全连通分量 的数量。 如果在子图中任意两个顶点之间都存在路径,并且子图中没有任何一个顶点与子图外部的顶点共享边,则称其为 连通分量 。 如果连通分量中每对节点之间都存在一条边,则称其为 完全连通分量 。 示例 1: 输入:n = 6, edges = [[0,1],[0…
leetcode.com 2026-07-11
🟡2685.count-the-number-of-complete-components
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
🟡2685.count-the-number-of-complete-components
🏷️ Tags
#depth_first_search #breadth_first_search #union_find #graph
Telegraph
count-the-number-of-complete-components
You are given an integer n. There is an undirected graph with n vertices, numbered from 0 to n - 1. You are given a 2D integer array edges where edges[i] = [ai, bi] denotes that there exists an undirected edge connecting vertices ai and bi. Return the number…