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Java - OOP (override, overload)
#java
#oop
#override
#overload
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#java
#oop
#override
#overload
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Java kursi haqida.txt
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Given a string and a non-negative int n, return a larger string that is n copies of the original string.
stringTimes("Hi", 2) → "HiHi"
stringTimes("Hi", 3) → "HiHiHi"
stringTimes("Hi", 1) → "Hi"
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public String stringTimes(String str, int n) {
String s = "";
for (int i=0; i<n; i++){
s = s + str;
}
return s;
}
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Given a string and a non-negative int n, we'll say that the front of the string is the first 3 chars, or whatever is there if the string is less than length 3. Return n copies of the front;
frontTimes("Chocolate", 2) → "ChoCho"
frontTimes("Chocolate", 3) → "ChoChoCho"
frontTimes("Abc", 3) → "AbcAbcAbc"
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public String frontTimes(String str, int n) {
String s = "";
if (str.length() > 2){
for (int i = 0; i< n; i++){
s += str.substring(0, 3);
}
}
if (str.length() > 1 && str.length() <= 2){
for (int i = 0; i< n; i++){
s += str.substring(0, 2);
}
}
if (str.length() > 0 && str.length() <= 1){
for (int i = 0; i< n; i++){
s += str.substring(0, 1);
}
}
return s;
}
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Given a string, return a new string made of every other char starting with the first, so "Hello" yields "Hlo".
stringBits("Hello") → "Hlo"
stringBits("Hi") → "H"
stringBits("Heeololeo") → "Hello"
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public String stringBits(String str) {
String s = "";
for(int i=0; i<str.length(); i+=2){
char c = str.charAt(i);
s += c;
}
return s;
}
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IntelliJ IDEA dasturini o'rnatish
Java va Kotlin dasturlash tillari uchun muhit
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Kotlin - OOP yordamida Registratsiya dasturini yaratish
#kotlin
#oop
#registration
#cleanCode
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Kotlin kursi haqida.txt
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