Islomga bag'ishlangan umr 1-qism

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Islomga bag'ishlangan umr 2-qism

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Assalomu aleykum Xurmatli dasturchilar. PROGRAMMERS kanalimizda savol - javob viktorinasini olib borayapmiz. Viktorinamizda berilayotgan savollar va javobllar yuqorida qolib ketganligini hisobga olgan holatda, viktorinamizdagi savol javoblarni @programmersQuiz_bot botiga joylab borayapmiz. Botga a'zo bo'ling. Hali savollar oldida ...

Botning Java bobiga yangi bo'lim, yangi savollarni va ularning javoblarini qo'shdik.

Viktorina bot

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#savol_java_begin_13
Umumiy markazda bo'lgan ikkita aylana radiusi berilgan. R1, R2 (R1>R2) Ularning yuzalari S1 va S2, ularning ayirmasini S3 aniqlang.

S1 = Pi*R1, S2 = Pi*R2, S3 = Pi*(R1-R2)

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#savol

#javob
Java dasturlash tilida
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("e = ");
float e = scanner.nextFloat();
float a0 = 2, ak, k = 1;
while (true) {
ak = 2 + 1 / a0;
k++;
if (Math.abs(ak - a0) < e) {
System.out.println("k = " + k);
System.out.println("a0 = " + a0);
System.out.println("ak = " + ak);
break;
}
a0 = ak;
}
}

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Lirik chekinish

Dasturlash mavzusidan biroz chekinganimiz uchun uzr, lekin barchamizni so'nggi manzilga kuzatuvchi odamlarning hikoyalarini eshitishni tavsiya qilamiz

Videoni ko'rish

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#savol

#javob
Kotlin dasturlash tilida
fun main() {
val scanner = Scanner(System.in)
print("e = ")
val e = scanner.nextFloat()
var a0 = 2f
var ak: Float
var k = 1f
while (true) {
ak = 2 + 1 / a0
k++
if (Math.abs(ak - a0) < e) {
println("k = $k")
println("a0 = $a0")
println("ak = $ak")
break
}
a0 = ak
}
}

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#savol_java_begin_13
Umumiy markazda bo'lgan ikkita aylana radiusi berilgan. R1, R2 (R1>R2) Ularning yuzalari S1 va S2, ularning ayirmasini S3 aniqlang.

S1 = Pi*R1, S2 = Pi*R2, S3 = Pi*(R1-R2)

#javob_java_begin_13
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("R1 = ");
float r1 = scanner.nextFloat();
System.out.print("R2 = ");
float r2 = scanner.nextFloat();
System.out.print("R3 = ");
float r3 = scanner.nextFloat();
float s1 = (float) Math.PI * r1 * r1;
float s2 = (float) (Math.PI * r2 * r2);
float s3 = (float) (Math.PI * (r1 - r2));
System.out.println("Birinchi aylananing yuzasi = " + s1);
System.out.println("Ikkinchi aylananing yuzasi = " + s2);
System.out.println("Ularning ayirmasi = " + s3);
}

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#savol_java_begin_14
Aylananing uzunligi L berilgan. Uning radiusi R va yuzasi S aniqlang.

L = 2*Pi*R, S = Pi*R*R Pi = 3.14

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#savol_14
a massiv elementlarini klaviaturadan kiriting va ularni ekranga chiqaring. k va l sonlarini kiriting ((k<l) k dan l gacha bo'lgan massiv elementlarini b massivga o'zlashtiring va ularni ekranga chiqaring?

#javob_14
#cpp
C++ dasturlash tilida yozilgan dastur kodi

#include <iostream>

using namespace std;

int main(){
int n, s=0, a[n], b[n], t=0, k, l;
cout << "Massiv elementlar sonini kiriting: ";
cin >> n;
cout << "a elementlarini kiriting: ";
for (int i = 0; i < n; i++) {
cin >> a[i];
}
cout << "a massiv elemenlari: ";
for (int i = 0; i < n; i++) {
cout << a[i] << " ";
}
cout << "\nk va l sonlarini kiriting: k < l sharti asosida" << endl;
cout << "k = ";
cin >> k;
cout << "l = ";
cin >> l;
for (int i = k; i <= l; i++) {
b[t++] = a[i];
}
cout << "b massiv elementlari: ";
for (int i = 0; i < t; i++) {
cout << b[i] << " ";
}
}

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#savol_14
a massiv elementlarini klaviaturadan kiriting va ularni ekranga chiqaring. k va l sonlarini kiriting ((k<l) k dan l gacha bo'lgan massiv elementlarini b massivga o'zlashtiring va ularni ekranga chiqaring?

#javob_14
#java
Java dasturlash tilida yozilgan dastur kodi

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Massiv elementlar sonini kiriting: ");
int n = scanner.nextInt();
int a[] = new int[n];
System.out.print("a massiv elementlarini kiriting: ");
for (int i = 0; i < a.length; i++) {
a[i] = scanner.nextInt();
}
System.out.print("a massiv elemenlari: ");
for (int i = 0; i < a.length; i++) {
System.out.print(a[i] + " ");
}
int b[] = new int[n];
int t = 0;
System.out.println("\nk va l sonlarini kiriting: k < l sharti asosida");
System.out.print("k = ");
int k = scanner.nextInt();
System.out.print("l = ");
int l = scanner.nextInt();
for (int i = k; i <= l; i++) {
b[t++] = a[i];
}
System.out.print("b massiv elementlari: ");
for (int i = 0; i < t; i++) {
System.out.print(b[i] + " ");
}
}

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#savol_14
a massiv elementlarini klaviaturadan kiriting va ularni ekranga chiqaring. k va l sonlarini kiriting ((k<l) k dan l gacha bo'lgan massiv elementlarini b massivga o'zlashtiring va ularni ekranga chiqaring?

#javob_14
#kotlin
Kotlin dasturlash tilida yozilgan dastur kodi

fun main(args: Array<String>) {
print("Massiv elementlar sonini kiriting: ")
val n = readLine()!!.toInt()
val a = IntArray(n)
print("a massiv elementlarini kiriting: ")
for (i in a.indices) {
a[i] = readLine()!!.toInt()
}
print("a massiv elemenlari: ")
for (i in a.indices) {
print(a[i].toString() + " ")
}
val b = IntArray(n)
var t = 0
println("\nk va l sonlarini kiriting: k < l sharti asosida")
print("k = ")
val k = readLine()!!.toInt()
print("l = ")
val l = readLine()!!.toInt()
for (i in k..l) {
b[t++] = a[i]
}
print("b massiv elementlari: ")
for (i in 0 until t) {
print(b[i].toString() + " ")
}
}

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#savol_java_begin_14
Aylananing uzunligi L berilgan. Uning radiusi R va yuzasi S aniqlang.

L = 2*Pi*R, S = Pi*R*R Pi = 3.14

#javob_java_begin_14
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("L = ");
float l = scanner.nextFloat();
float r = (float) (l / (2 * Math.PI));
float s = (float) (Math.PI * r * r);
System.out.println("Radiusi = " + r);
System.out.println("Yuzasi = " + s);
}

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#savol_java_begin_15
Aylananing yuzasi S berilgan. Uning diametri d va radiusi R aniqlang.

L = 2*Pi*R, S = Pi*R*R Pi = 3.14

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Assalomu aleykum xurmatli dasturchilar bugundan boshlab sizlar bilan Java dasturlash tilida fayl ochish, faylga yozish, fayldan o'qish mavzularini ko'rib chiqishni boshlaymiz.

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Java - Fayl ochish 1-qism

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Java - Fayl ochish 2-qism

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#savol_java_begin_15
Aylananing yuzasi S berilgan. Uning diametri d va radiusi R aniqlang.

L = 2*Pi*R, S = Pi*R*R Pi = 3.14

#javob_java_begin_15
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("S = ");
float s = scanner.nextFloat();
float r = (float) Math.sqrt(s / Math.PI);
float d = 2 * r;
System.out.println("Radiusi = " + r);
System.out.println("diametri = " + d);
}

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#savol_java_begin_16
Sonlar o'qida ikkita nuqta orasidagi masofani aniqlang. |x2-x1|

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Java - Faylga yozish 1-qism

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Java - Faylga yozish 2-qism

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