JavaScript online compile

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Python online compile

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intelliJ IDEA
Java dasturlash tili muhiti

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JDK - 17
Java dasturlash tili muhitida ishlash uchun o'rnatiladi

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intelliJ IDEA
Java dasturlash tili muhitini o'rnatish videodarsligi

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Assalomu aleykum Xurmatli dasturchilar. PROGRAMMERS kanalimizda savol - javob viktorinasini olib borayapmiz. Viktorinamizda berilayotgan savollar va javobllar yuqorida qolib ketganligini hisobga olgan holatda, viktorinamizdagi savol javoblarni @programmersQuiz_bot botiga joylab borayapmiz. Botga a'zo bo'ling. Hali savollar oldida ...

Botga yangi savollarni va ularning javoblarini qo'shdik.

Ha aytgancha botga yangi Kotlin bo'limini qo'shdik 😊

👉 /start ni yuborib, yangi bo'limni qabul qiling.

Viktorina bot

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#savol_cpp_begin_3
To'g'ri to'rtburchakning tomonlari a va b berilgan. Uning yuzasi S = a*b va perimetrini P = 2*(a+b) aniqlang.

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C++ dasturi

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#savol_cpp_begin_3
To'g'ri to'rtburchakning tomonlari a va b berilgan. Uning yuzasi S = a*b va perimetrini P = 2*(a+b) aniqlang.

#javob_cpp_begin_3
#include <iostream>
using namespace std;
int main(){
int a, b, s, p;
cout << "a = ";
cin >> a;
cout << "b = ";
cin >> b;
p = 2 * (a + b);
s = a * b;
cout <<"Perimetri = " << p << endl;
cout <<"Yuzasi = " << s;
}

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#savol

#javob
Kotlin dasturlash tilida
fun main() {
print("n = ")
val n = readLine()!!.toInt()
var k = 0
while (k * k <= n) {
k++
}
print("k = $k")
}

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#savol_cpp_begin_4
Aylananing diametri d berilgan. Uning uzunligini aniqlang. L = Pi*d Pi = 3.14

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#savol
Z massivning maksimal va minimal elementlaridan boshqa barcha elementlarini, o'rta geometrik qiymatidan kichik bo'lgan elementlari sonini toping?

#javob
Java dasturlash tilida

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("n = ");
int n = scanner.nextInt();
int[] z = new int[n];
for (int i = 0; i < z.length; i++) {
z[i] = scanner.nextInt();
}
int s = 1;
System.out.print("Siz kiritigan massiv elementlari: ");
for (int j : z) {
s *= j;
System.out.print(j + " ");
}
int min = z[0];
int max = z[0];
for (int j : z) {
if (max < j) {
max = j;
}
if (min > j) {
min = j;
}
}
System.out.println("\nZ massivning max elementi: " + max);
System.out.println("Z massivning min elementi: " + min);
int a = 1;
a = (s / max) / min;
double ortaGeoQiymat = Math.pow(a, (1.0 / (n - 2)));
int t = 0;
for (int j : z) {
if (ortaGeoQiymat > j) {
t++;
}
}
System.out.print("O'rta geometrik qiymati = " + ortaGeoQiymat);
System.out.println("a = " + a);
System.out.println("O'rta geometrik qiymatidan kichik elemetlari soni = " + (t - 1));
}

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#savol
Z massivning maksimal va minimal elementlaridan boshqa barcha elementlarini, o'rta geometrik qiymatidan kichik bo'lgan elementlari sonini har doim 1 ta chiqarkan. Shu gap rostmi?

Kommentariyada fikrlaringizni bildiring

#case_18
Java dasturlash tili

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("100 - 999 oralig'idagi sonlardan birini kiriting");
System.out.print("n = ");
int n = scanner.nextInt();
int yuzlar = n / 100;
int onlar = (n / 10) % 10;
int birlar = n % 10;
switch (yuzlar){
case 1 -> System.out.print("Bir yuz ");
case 2 -> System.out.print("Ikki yuz ");
case 3 -> System.out.print("Uch yuz ");
case 4 -> System.out.print("To'rt yuz ");
case 5 -> System.out.print("Besh yuz ");
case 6 -> System.out.print("Olti yuz ");
case 7 -> System.out.print("Yetti yuz ");
case 8 -> System.out.print("Sakkiz yuz ");
case 9 -> System.out.print("To'qqiz yuz ");
}
switch (onlar){
case 1 -> System.out.print("o'n ");
case 2 -> System.out.print("yigirma ");
case 3 -> System.out.print("o'ttiz ");
case 4 -> System.out.print("qirq ");
case 5 -> System.out.print("ellik ");
case 6 -> System.out.print("oltmish ");
case 7 -> System.out.print("yetmish ");
case 8 -> System.out.print("sakson ");
case 9 -> System.out.print("to'qson ");
}
switch (birlar){
case 1 -> System.out.print("bir");
case 2 -> System.out.print("ikki");
case 3 -> System.out.print("uch");
case 4 -> System.out.print("to'rt");
case 5 -> System.out.print("besh");
case 6 -> System.out.print("olti");
case 7 -> System.out.print("yetti");
case 8 -> System.out.print("sakkiz");
case 9 -> System.out.print("to'qqiz");
}
}

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#savol
100 dan 800 gacha diapazonda bo`lgan n natural soni berilgan. n dan katta bo`lgan 3 xonali
sonlarni qanchaligini aniqlang

2 - usul
#javob
Java dasturlash tilida
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("100 - 800 oralig'idagi son kiriting: ");
int n = scanner.nextInt();
int t = 0;
for (int i = 100; i <= 800; i++) {
if (n < 800) {
t++;
n++;
if (n == 800) {
break;
}
}
}
System.out.println("800 gacha bo'lgan 3 xonali sonlar " + t + " ta");
}

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#savol
100 dan 800 gacha diapazonda bo`lgan n natural soni berilgan. n dan katta bo`lgan 3 xonali
sonlarni qanchaligini aniqlang

1 - usul
#javob
Java dasturlash tilida
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("100 - 800 oralig'idagi son kiriting: ");
int n = scanner.nextInt();
int t = 0;
t = 800-n;
System.out.println(n + " dan 800 gacha bo'lgan 3 xonali sonlar " + t + " ta");
}

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#savol

#javob
Kotlin dasturlash tilida
fun main() {
print("n = ")
var n = readLine()!!.toInt()
var k = 0
while (3 <= n) {
n /= 3
k++
}
print("k = $k")
}

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