Code With Python
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This channel delivers clear, practical content for developers, covering Python, Django, Data Structures, Algorithms, and DSA – perfect for learning, coding, and mastering key programming skills.
Admin: @HusseinSheikho || @Hussein_Sheikho
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A bit of basics. Day 3: Calendar in Python

There is a built-in module in Python called calendar. We can import this module to display the calendar. There are many things you can do with the calendar.

Let's say we want to see the calendar for April 2022. We use the month class from the calendar module and pass the year and month as arguments. See below:

import calendar

month = calendar.month(2022, 4)
print(month)


There are many other things you can do with calendar. For example, you can use it to check whether a given year is a leap year or not. Let's check if 2022 is a leap year.

import calendar

month = calendar.isleap(2022)
print(month)


False

👉 https://t.iss.one/DataScience4
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How to Use the OpenRouter API to Access Multiple AI Models via Python

📖 Access models from popular AI providers in Python through OpenRouter's unified API with smart routing, fallbacks, and cost controls.

🏷️ #intermediate #ai #api
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A bit of Python basics. Day 4: Getting the current time and date

The code below shows how to get the current time using the datetime module. The now() method returns a datetime object representing the current date and time according to the system clock. The strftime() method formats the time for the desired output. This code shows how to use the datetime module together with the strftime() method to get a formatted time string in the format of hours, minutes, and seconds.

from datetime import datetime

time_now = datetime.now().strftime('%H:%M:%S')
print(f'Current time: {time_now}')


Current time: 17:37:28


What if we want to return today's date? We can use date from the datetime module. Below, the today() method is used:

from datetime import date

today_date = date.today()
print(today_date)


2023-09-20


👉 https://t.iss.one/DataScience4
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graphical user interface (GUI) | Python Glossary

📖 A visual way of interacting with a program through windows, buttons, and other on-screen elements.

🏷️ #Python
2
How to Run Your Python Scripts and Code

📖 Learn how to run Python scripts from the command line, REPL, IDEs, and file managers on Windows, Linux, and macOS. Master all execution approaches.

🏷️ #basics #best-practices #devops #python
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Gift Cards

📖 Give the Gift of Real Python with a membership gift card. An easy way to give joy to the Pythonistas in your life.

🏷️ #Python
1
Lovable | AI Coding Tools

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🏷️ #Python
1
Quiz: Hands-On Python 3 Concurrency With the asyncio Module

📖 Test your asyncio skills with a focused quiz on coroutines, event loops, generators, and IO-bound concurrency in Python 3.

🏷️ #advanced #python
1
A bit of Python basics. Day 6 - Exchanging variable values

In Python, you can swap variables after they have already been assigned objects. Below, we first assign 20 to the variable x and 30 to the variable y, and then swap them: x becomes 30, and y becomes 20. This method is called tuple packing/unpacking.

x, y = 20, 30
x, y = y, x

print('x is: ', x)
print('y is: ', y)


x is 30
y is 20


You can also use the XOR (exclusive or) operator to swap variables. This is a three-step method. In the example below, we swap the values of x and y.

x = 20
y = 30

# step one
x ^= y
# step two
y ^= x
# step three
x ^= y

print(f'x is: {x}')
print(f'y is: {y}')


x is: 30
y is: 20


You can also use arithmetic operations (addition and subtraction) to swap variables without a temporary variable. However, this method is recommended for swapping numeric data types. Here's an example:

# Use arithmetic operations
x = 5
y = 10

x = x + y
y = x - y
x = x - y

print("After swapping:")
print("x =", x)
print("y =", y)


After swapping:
x = 10
y = 5


As a result of these arithmetic operations, the values of x and y have actually been swapped. After the swap, x contains the original value of y (10), and y contains the original value of x (5).

This method of swapping variables without a temporary variable is based on the fact that when you add or subtract the value of one variable from another, you can effectively swap their values without the need for additional storage.

👉 https://t.iss.one/DataScience4
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This channels is for Programmers, Coders, Software Engineers.

0️⃣ Python
1️⃣ Data Science
2️⃣ Machine Learning
3️⃣ Data Visualization
4️⃣ Artificial Intelligence
5️⃣ Data Analysis
6️⃣ Statistics
7️⃣ Deep Learning
8️⃣ programming Languages

https://t.iss.one/addlist/8_rRW2scgfRhOTc0

https://t.iss.one/Codeprogrammer
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Build Your Weekly Python Study Schedule: 7 Days to Consistent Progress

📖 Create a weekly Python study schedule you can stick to. Build a realistic 7-day plan, stay consistent, and turn learning Python into a sustainable habit.

🏷️ #basics #career
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OpenCode | AI Coding Tools

📖 An open-source terminal AI coding agent with support for over 75 AI models and IDE integrations.

🏷️ #Python
Quiz: Dependency Management With Python Poetry

📖 Test your knowledge of Python Poetry, from installation and virtual environments to lock files, dependency groups, and updates.

🏷️ #intermediate #best-practices #devops #tools
A bit of Python basics. Day 7. Counting the number of occurrences of an element

If you need to find out how many times an element appears in an iterable collection, you can use the Counter class from the collections module. Counter() returns a dictionary with the number of times each element appears in the sequence. Let's say we want to find out how many times the name Peter appears in the following list. We can use Counter(). See below:

from collections import Counter

list1 = ['John', 'Kelly', 'Peter', 'Moses', 'Peter']

count_peter = Counter(list1).get("Peter")

print(f'The name "Peter" appears in the list '
      f'{count_peter} times.')


Output:

The name "Peter" appears in the list 2 times.

Another way to do this is with a regular for loop. We create a count variable and increase it by 1 each time we find the name Peter in the sequence. This is a naive approach. See below:

list1 = ['John', 'Kelly', 'Peter', 'Moses', 'Peter']
# Create a count variable
count = 0
for name in list1:
    if name == 'Peter':
        count +=1
print(f'The name "Peter" appears in the list'
      f' {count} times.')


Output:

The name "Peter" appears in the list 2 times.

Lists and other iterable data structures in Python have a built-in count() method, which allows us to count the number of occurrences of a specific element. We can use count() to count how many times Peter appears in the list.

list1 = ['John', 'Kelly', 'Peter', 'Moses', 'Peter']

print(f'The name "Peter" appears in the list '
      f'{list1.count("Peter")} times.')


Output:

The name "Peter" appears in the list 2 times.

👉 https://t.iss.one/DataScience4
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⚡️ Python code that works, but does extra work 100 times over

This Python code looks normal.
It works.
It passes the tests.
But it does extra work dozens, and sometimes hundreds of times.

The most common reason is that you accidentally turn a linear algorithm into a quadratic one.

A typical scenario:
- there's a list
- inside the loop, you repeatedly do in, count, index
- everything works quickly with small data
- on real data, the application starts to "slow down for no reason"

The problem is that:
- list is O(n) for searching
- searching inside the loop = O(n²)
- Python honestly does the work you asked it to do

Pros don't think about "whether it works or not", but how many extra operations are being performed.

The correct approach:
- if you need membership checks, use set
- if you're counting elements, use dict or Counter
- if the data doesn't change, pre-calculate it once

This technique is one of the most common sources of hidden performance bugs in Python code.


# Bad: O(n²)
users = ["alice", "bob", "carol", "dave"]

for u in users:
if u in users: # full list traversal every time
process(u)


# Good: O(n)
users = ["alice", "bob", "carol", "dave"]
users_set = set(users)

for u in users:
if u in users_set:
process(u)
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reversed() in Python - what supports it and what doesn't

The function reversed() is built-in in Python, but it doesn't work with all data types

✓ Lists - it works
reversed([1, 2, 3]) returns an iterator
list(reversed([1, 2, 3])) → [3, 2, 1]

✓ Tuples - it also works
reversed((1, 2, 3)) can be easily iterated

✗ Sets - not supported
reversed({1, 2, 3}) → TypeError
Why? Sets don't have a fixed order, so they can't be "reversed"

If you need to reverse a set:
list(reversed(list({1, 2, 3})))
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A bit of #Python basics. Day 8 - Flatten a nested list

I'll show you three (3) ways to flatten a two-dimensional list. The first method uses a for loop, the second uses the itertools module, and the third uses list comprehension.

⚙️ Using a for loop:

For this method, we use a nested for loop. The outer loop iterates over the inner lists, and the inner loop accesses the elements in the inner lists.

# In [19]:
list1 = [[1, 2, 3],[4, 5, 6]]

newlist = []
for list2 in list1:
    for j in list2:
        newlist.append(j)

print(newlist)


[1, 2, 3, 4, 5, 6]

⚙️ Using the itertools module:

The itertools.chain.from_iterable() function from the itertools module can be used to flatten a nested list. This method may not be suitable for deeply nested lists.

# In [20]:
import itertools

list1 = [[1, 2, 3],[4, 5, 6]]

flat_list = list(itertools.chain.from_iterable(list1))
print(flat_list)


[1, 2, 3, 4, 5, 6]

You can see that the nested loop has been flattened.

⚙️ Using list comprehension

If you don't want to import itertools or write a regular for loop, you can simply use list comprehension.

# In [21]:
list1 = [[1, 2, 3], [4, 5, 6]]

flat_list = [i for j in list1 for i in j]
print(flat_list)


[1, 2, 3, 4, 5, 6]

List comprehension is well suited for moderately nested lists. For deeply nested lists, it is not suitable, as the code becomes harder to read.

⚙️ Using a generator function

You can create a generator function that yields elements from the nested list, and then convert the generator into a list.

# In [22]:
def flatten_generator(nested_list):
    for sublist in nested_list:
        for item in sublist:
            yield item

list1 = [[1, 2, 3], [4, 5, 6]]

flat_list = list(flatten_generator(list1))
flat_list


Out[22]: [1, 2, 3, 4, 5, 6]

The generator method is suitable for flattening large or deeply nested lists. This is because generators are memory-efficient.

👉 https://t.iss.one/DataScience4
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