def print_hashtags(middle_count=9):
    top_range = list(range(1, middle_count + 1, 2)) # 1, 3, 5, ...
    bottom_range = list(reversed(top_range))[1:] # 9, 7, 5, 3, ...
    latest_range = top_range + bottom_range # ex [input = 7]: 1, 3, 5, 7, 5, 3, 1
    for i in latest_range:
        print((i * '#').center(middle_count)) # each row printing here...

print_hashtags(middle_count=int(input('Enter the middle row hashtag counts: ')))

n = 5
set(map(lambda i:print("{} {}".format(abs(n - i) * ' ', (2 * (n - abs(n-i)) - 1) * '#')), range(1, 2 * n)))

 int i, j, c, count, counts;
            count = 12;
            for (i = 0; i <= 7; i += 2)
            {
                for (c = 0; c <= count; c++)
                {
                    Console.Write(" ");
                }
                for (j = 0; j <= i; j++)
                {
                    System.Console.Write("#");
                }
                Console.WriteLine();
                count--;
            }
            //############################################
            counts = 10;
                for (i = 7; i >= 1; i-=2)
                {
                    for (c = 1; c <= counts; c++)
                    {
                        Console.Write(" ");
                    }
                    for (j = 1; j <= i; j++)
                    {
                        System.Console.Write("#");
                    }
                    Console.WriteLine();
                    counts++;
                }
                    Console.ReadKey();

#!/usr/bin/python
# Cod By Armia_Evil
# Telegram @Armia_Evil

z = 0; count = 3 ; count1 = -1 
s = ""; f = ""

counts = 9; counts1 = 0; q = 0
s1 = ""; f1 = ""; f2 = ""

######################### مثلث اول
while z <= 8:    ## حلقه بي نهايت با چرخش مشخص
    count1 += 2 ## متير کانت 1 رو 2 واحد اضافه ميکنه
    
    for i in range(9): ## حلقه فور با تعداد چرخش 9 اين حلقه باعث ميشه بعد از چاپ # به خط بعدي بره
        if i == count1: ## برسي شرط
            for c in range(count): ## حلقه براي فاصله    
                f += " "
            for j in range(i): ## اين حلقه تعدا # رو چاپ ميکنه
                s += "#"
                
            print(f,s) ## در اينجا اول فاصله و بعد تعداد # رو چاپ ميکنه
            print(" ")

            count -= 1
            s = ""
            f = ""
    z += 1
########################## مثلث دوم
    
while q <= 8:
    counts -= 2
    
    for a1 in range(8):
        if a1 == counts:
            for c1 in range(counts1):       
                f2 += " "            
            for b in range(a1):
                s1 += "#"
       
            print(f2,s1)
            s1 = ""
            f2 = ""
            print("")
            counts1 += 1
    q += 1

print('\n'.join(map(lambda i: ((2*(n-abs(n-i))-1)*'#').center(2*n-1),range(1,2*n))))